Symmetry and convexity · Question 5
Symmetry and convexity in geometric inequalities · Historical workshop question
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If we replace condition in the theorem with $\nabla^2 W(x) \geq F(x) \, Id$, can we obtain better results?
## Question context
\begin{theorem}[Caffarelli]
Let $T = \nabla \Phi: \mu \to \nu$ be a Brenier map, where $\mu$ and $\nu$ are probability measures with densities $e^{-V(x)}$ and $e^{-W(x)}$. Suppose that
$$
\nabla^2 W(x) \geq K \, Id,
$$
for some constant $K$. Then for any $e \in S^{n-1}$
$$
\sup\limits_{ x \in \mathbb{R}^n } \Phi^2_{ e e } \leq \frac1K \sup\limits_{x \in \mathbb{R}^n} V_{ee},
$$
where $\Phi_{e}$ denotes directional derivative.
\end{theorem}
Historical workshop record. Current open/solved status has not been independently reassessed.
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If we replace condition in the theorem with , can we obtain better results?
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Background
Question context
\begin{theorem}[Caffarelli] Let be a Brenier map, where and are probability measures with densities and . Suppose that
for some constant . Then for any
\sup\limits_{ x \in \mathbb{R}^n } \Phi^2_{ e e } \leq \frac1K \sup\limits_{x \in \mathbb{R}^n} V_{ee}, $$ where $\Phi_{e}$ denotes directional derivative. \end{theorem}Progress & source assessment
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- [1]Symmetry and convexity in geometric inequalities link
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