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OP-11957OpenNumber theory

Euler's Sum of Powers Conjecture

Euler's Sum of Powers Conjecture. Moderately interesting problem from Epoch AI’s FrontierMath: Open Problems; answers are checked by a verifier program.

Epoch field label “Diophantine” mapped to MSC2020 11D41 for Euler's Sum of Powers Conjecture. https://epoch.ai/frontiermath/open-problems/euler-sum-of-powers Not an author-supplied code.

Licensed source statementAs of Epoch AI data archive updated 2026-10-07; status as labeled by EpochSource & evidence ↓

Problem statement

This problem asks for a counterexample to Euler’s sum of powers conjecture. Specifically, the problem asks: for some k>5k > 5, find nonzero integers a1,…,aka_1, \ldots, a_k such that ∑i=1k−1aik=akk\sum_{i=1}^{k-1} a_i^k = a_k^k.

Euler conjectured that no solution to the above equation exists for k>2k > 2. The conjecture is true for k=3k = 3 (which is a special case of Fermat’s Last Theorem), but false for k=4k = 4 and k=5k=5. No counterexample for k>5k > 5 is known.

Experts expect that this problem is solvable, and the verifier can check a correct counterexample. The main risk with this problem is a brute-force solution for a single value of kk may not be very interesting or insightful. An ideal solution would either be a construction that works for all k>5k > 5, or an efficient way of generating counterexamples.

Lean 4

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Background

FrontierMath: Open Problems lists this problem with notability “Moderately interesting”, field “Diophantine” and type “Counterexample; Integer Solution”. Each problem has a bespoke verifier program, so a proposed answer can be checked automatically.

Verifiable task — Epoch prompt, verbatim

In 1769 Leonhard Euler conjectured that for every integer n > 2, no sum of fewer than n positive n-th powers can itself be an n-th power. In its tightest form this says the equation

    a_1^n + a_2^n + ... + a_{n-1}^n = b^n

has no solution in positive integers: with only n-1 terms on the left, an n-th power cannot be reached. Euler's conjecture stood for nearly two centuries. It was finally refuted for n = 5 by Lander and Parkin in 1966, who found

    27^5 + 84^5 + 110^5 + 133^5 = 144^5,

and later for n = 4 by Elkies and Frye. But for every exponent n > 5, no counterexample is known, and whether any exists remains open.

## Task

Find an integer k > 5 and positive integers a_1, ..., a_{k-1}, a_k such that

    a_1^k + a_2^k + ... + a_{k-1}^k = a_k^k.

The length of your list determines the exponent: if you submit k integers, the exponent is k, the first k-1 are summed, and the last is the right-hand side. So a valid submission of k integers is exactly a counterexample to Euler's conjecture for exponent k.

## Submission

Submit your list of integers (a_1, ..., a_k) using the submit tool. Every integer must be positive, as in the statement of the conjecture; zero or negative entries are rejected. There is no bound on their magnitude. Your submission is checked exactly with arbitrary-precision integer arithmetic, so an approximate or rounded answer will not be accepted.

Progress & source assessment

Epoch lists this problem as unsolved in its data archive updated 7 October 2026. Earlier AI attempts are not displayed by Epoch.

References
  1. [1]Epoch AI, ‘FrontierMath: Open Problems’. Published online at epoch.ai. Retrieved from https://epoch.ai/frontiermath/open-problems (data updated 7 October 2026). — Euler's Sum of Powers Conjecture linkCC BY 4.0 (Epoch AI data and problem pages); attributed reproduction of problem descriptions and verbatim task prompts.

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