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OP-9300OpenGraph theory

Erdős #1011 · graph theory

Let fr(n)f_r(n) be minimal such that every graph on nn vertices with ≥fr(n)\geq f_r(n) edges and chromatic number ≥r\geq r contains a triangle. Determine fr(n)f_r(n).

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Source reports OPENAs of 2026-09-08Source & evidence ↓

Problem statement

Let fr(n)f_r(n) be minimal such that every graph on nn vertices with ≥fr(n)\geq f_r(n) edges and chromatic number ≥r\geq r contains a triangle. Determine fr(n)f_r(n).

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Background

Turán's theorem implies f2(n)=⌊n2/4⌋+1f_2(n)=\lfloor n^2/4\rfloor+1. Erdős and Gallai [Er62d] proved f3(n)=⌊14(n−1)2⌋+2f_3(n)=\lfloor \frac{1}{4}(n-1)^2\rfloor+2.

Simonovits showed in his PhD thesis (see the discussion on p. 358 of [Si74]) that

fr(n)=n24−g(r)2n+O(1),f_r(n)=\frac{n^2}{4}-\frac{g(r)}{2}{n}+O(1),

where g(r)g(r) is the largest mm such that, for any triangle-free graph with chromatic number ≥r\geq r, at least mm vertices of GG need to be removed to obtain a bipartite graph. Simonovits [Si74] notes

log⁡rlog⁡log⁡rr2≪g(r)≪(log⁡r)2r2.\frac{\log r}{\log\log r}r^2 \ll g(r) \ll (\log r)^2r^2.

Hunter in the comments has noted that other results imply g(r)≍r2log⁡rg(r)\asymp r^2\log r - in fact

(1/2−o(1))r2log⁡r≤g(r)≤(2+o(1))r2log⁡r.(1/2-o(1))r^2\log r\leq g(r)\leq (2+o(1))r^2\log r.

The lower bound follows from work of Davies and Illingworth [DaIl22] (see [1104]). The upper bound follows from work of Hefty, Horn, King, and Pfender [HHKP25] on R(3,k)R(3,k).

Ren, Wang, Wang, and Yang [RWWY24] showed that, for n≥150n\geq 150,

f4(n)=⌊(n−3)24⌋+6.f_4(n)=\left\lfloor\frac{(n-3)^2}{4}\right\rfloor+6.

Progress & source assessment

The source labels this entry OPEN in the 2026-09-08 snapshot. Editorial progress notes are reproduced as source commentary, not independently verified results. Prize amounts and Lean badges at the source are not local awards or verification.

References
  1. [1]Thomas Bloom (ed.), Erdős Problems #1011 link

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