OpenFrontiers
← Back to the index
OP-9392OpenNumber theory

Erdős #1181 · number theory

Let q(n,k)q(n,k) denote the least prime which does not divide ∏1≤i≤k(n+i)\prod_{1\leq i\leq k}(n+i). Is it true that there exists some c>0c>0 such that, for all large nn,

q(n,log⁡n)<(1−c)(log⁡n)2?q(n,\log n)<(1-c)(\log n)^2?

Inferred from the community field; finer classification has not been reviewed.

Source reports OPENAs of 2026-09-08Source & evidence ↓

Problem statement

Let q(n,k)q(n,k) denote the least prime which does not divide ∏1≤i≤k(n+i)\prod_{1\leq i\leq k}(n+i). Is it true that there exists some c>0c>0 such that, for all large nn,

q(n,log⁡n)<(1−c)(log⁡n)2?q(n,\log n)<(1-c)(\log n)^2?

Lean 4

Not yet attached

No Lean statement or proof is attached yet. Have a formalization? Share its source to add it to this problem.

Background

The upper bound q(n,log⁡n)≤(1+o(1))(log⁡n)2q(n,\log n)\leq (1+o(1))(\log n)^2 follows from observing that the primorial of q(n,k)q(n,k) is at most ∏1≤i≤k(n+i)\prod_{1\leq i\leq k}(n+i).

Probabilistic heuristics described by Tao in the comments of [457] suggest that

q(n,log⁡n)≪log⁡log⁡nlog⁡log⁡log⁡nlog⁡nq(n,\log n)\ll \frac{\log\log n}{\log\log\log n}{\log n}

for all nn.

[457] concerns lower bounds for q(n,log⁡n)q(n,\log n) (and in particular the constructions described there proved that the above upper bound would be best possible).

Progress & source assessment

The source labels this entry OPEN in the 2026-09-08 snapshot. Editorial progress notes are reproduced as source commentary, not independently verified results. Prize amounts and Lean badges at the source are not local awards or verification.

References
  1. [1]Thomas Bloom (ed.), Erdős Problems #1181 link

Recorded progress

Add yours →

Nothing recorded yet. A pointer to a paper the entry is missing counts.

Machine attempts

0 recorded

Attempts run against the statement below and are recorded in full, including the failures. The point is to stop the next model — and the next person — from re-walking a road that is already known to end. Each attempt costs 25 credits.

No machine attempts recorded.

Sign in to run an attempt. New accounts start with enough credits for ten.

Discussion

0 notes

Notes are for clarifying the statement, flagging a missing reference, or recording why an approach fails. Claimed solutions belong in a submission, where they can be reviewed.

No notes yet.

Sign in to add a note.