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OP-0010OpenCombinatorics$5,000 prize

Erdős's conjecture on arithmetic progressions

If the reciprocals of a set of integers diverge, must the set contain arbitrarily long arithmetic progressions?

Inferred from the community field; finer classification has not been reviewed.

Source reports OPENAs of 2026-09-08Source & evidence ↓

Problem statement

Let A⊆NA \subseteq \mathbb{N} satisfy ∑a∈A1/a=∞\sum_{a\in A} 1/a = \infty. Must AA contain arithmetic progressions of every finite length?

Lean 4

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Formal statement

The formalization is available at the source below; its code is not attached here yet.

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A source attachment or link is not a verified proof. The statement’s correspondence with the original question needs human review.

Proofs & verification

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Background

Erdős offered US$5,000 for the general conjecture. The three-term case is resolved: the quantitative bound of Bloom and Sisask (2020) is sufficient for every set with divergent reciprocal sum. The source snapshot of 8 September 2026 lists the general conjecture as open.

Why it matters

The conjecture would imply the Green–Tao theorem on progressions in the primes as an immediate corollary, since the primes have divergent reciprocal sum. It is the natural "density-free" strengthening of Szemerédi's theorem.

Progress & source assessment

  • Szemerédi's theorem handles sets of positive upper density.
  • Bloom and Sisask (2020) resolved the three-term case of the divergent-reciprocal-sum conjecture; no additional rate of divergence is needed.
  • Kelley and Meka (2023) subsequently established much stronger bounds for sets avoiding three-term progressions.
  • The general question for arbitrarily long progressions remains listed as open in Erdős Problems #3, snapshot 8 September 2026.
References
  1. [1]Z. Kelley, R. Meka, Strong bounds for 3-progressions (2023). link
  2. [2]Formal Conjectures — Erdős Problem 3 link

Recorded progress

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Discussion

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