Let ζ(s) denote the analytic continuation of ∑n≥1n−s to C∖{1}. The function has trivial zeros at the negative even integers. The hypothesis asserts that every other zero ρ satisfies
Re(ρ)=21.
Equivalently, for every ε>0,
π(x)=li(x)+O(x1/2+ε),
where π(x) counts primes up to x and li is the logarithmic integral.