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OP-6947Status unassessedCombinatorics

Upper bound on the independence number of a connected graph

TheoremDB P8248 · Candidate awaiting source review

Inferred from the community field; finer classification has not been reviewed.

Source candidate · not reviewedAs of 2026-09-08Source & evidence ↓

Problem statement

Let GG be a finite simple connected graph on at least two vertices such that its complement G‾\overline{G} is also connected. For each vertex vv of GG, let l(v)l(v) denote the independence number of the subgraph induced by the neighborhood of vv in GG. Let λ=max⁡v∈V(G)l(v)\lambda = \max_{v \in V(G)} l(v). Let diam(G‾)\mathrm{diam}(\overline{G}) denote the diameter of the complement graph G‾\overline{G}, i.e., the maximum over all pairs of vertices of the length of a shortest path between them in G‾\overline{G}. Prove that the independence number α(G)\alpha(G) satisfies

α(G)≤⌈λ+12⋅diam(G‾)2⌉.\alpha(G) \leq \left\lceil \frac{\lambda + \frac{1}{2} \cdot \mathrm{diam}(\overline{G})}{2} \right\rceil.

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Lean 4

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Formal statement

Lean 4
theorem conjecture100 (G : SimpleGraph α) [DecidableRel G.Adj] (h : G.Connected) :
    let maxL := (Finset.univ.image (indepNeighborsCard G)).max' (by simp)
    (G.indepNum : ℝ) ≤ ⌈((maxL : ℝ) + (1 / 2) * (degreeL2Norm Gᶜ : ℝ)) / 2⌉

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Proofs & verification

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Progress & source assessment

Source-reported assessment, retrieved 8 September 2026. Frontier Science has not independently reviewed this status.

Open. No signed Lean verification is attached to this problem or its selected resolution.

This record is in the source backlog; its novelty and unresolved status have not passed source review.

References
  1. [1]TheoremDB P8248 link
  2. [2]Source formal statement (not locally verified) link

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