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OP-6954Status unassessedAnalysis

Value Distribution of Entire Functions with Fabry Gaps

TheoremDB P9026 · Candidate awaiting source review

Source candidate · not reviewedAs of 2026-09-08Source & evidence ↓

Problem statement

An entire function is a complex-valued function that is holomorphic on the entire complex plane. A sequence of natural numbers n:N→Nn : \mathbb{N} \to \mathbb{N} is said to have Fabry gaps if lim⁡k→∞nkk=∞\displaystyle\lim_{k \to \infty} \frac{n_k}{k} = \infty. Let f:C→Cf : \mathbb{C} \to \mathbb{C} be an entire function with power series expansion f(z)=∑k=0∞akznk\displaystyle f(z) = \sum_{k=0}^{\infty} a_k z^{n_k} where the coefficients ak∈Ca_k \in \mathbb{C} are all nonzero and the sequence of exponents (nk)(n_k) has Fabry gaps, meaning the series converges for all z∈Cz \in \mathbb{C}. Does ff assume every complex value infinitely often? That is, for every z∈Cz \in \mathbb{C}, is the set {x∈C:f(x)=z}\{x \in \mathbb{C} : f(x) = z\} infinite?

Lean 4

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Formal statement

Lean 4
theorem erdos_517 : answer(sorry) ↔ ∀ {f : ℂ → ℂ} {n : ℕ → ℕ} (hn : HasFabryGaps n)
    {a : ℕ → ℂ} (ha : ∀ k, a k ≠ 0) (hf : ∀ z, HasSum (fun k => a k * z ^ n k) (f z)) (z : ℂ),
    {x : ℂ | f x = z}.Infinite

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Proofs & verification

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Progress & source assessment

Source-reported assessment, retrieved 8 September 2026. Frontier Science has not independently reviewed this status.

Open. No signed Lean verification is attached to this problem or its selected resolution.

This record is in the source backlog; its novelty and unresolved status have not passed source review.

References
  1. [1]TheoremDB P9026 link
  2. [2]Source formal statement (not locally verified) link

Recorded progress

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