OpenFrontiers
← Back to the index
OP-9762Status unassessedComputational complexity

Conjectures in Complexity Theory

Conjectures in Complexity Theory

Inferred from the community field; finer classification has not been reviewed.

Specialist source · status unassessedAs of 2026-09-10Source & evidence ↓

Problem statement

P_ne_NP

P ≠ NP:

The conjecture that the complexity classes P and NP are not equal.

NP_ne_coNP

NP ≠ coNP:

The conjecture that the complexity classes NP and coNP are not equal.

Lean 4

No Lean submitted

Formal statement

Lean 4
/-
Copyright 2025 The Formal Conjectures Authors.

Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at

    https://www.apache.org/licenses/LICENSE-2.0

Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
-/
import FormalConjecturesUtil

/-!
# Conjectures in Complexity Theory

This file contains formal statements of some of the main open conjectures
in complexity theory, including

- the P vs NP problem
- the NP vs coNP problem

*References:*
- [Wikipedia](https://en.wikipedia.org/wiki/P_versus_NP_problem)
- [The Clay Institute](https://www.claymath.org/millennium/p-vs-np/)
-/

namespace ComplexityTheory

/--
**P ≠ NP**:

The conjecture that the complexity classes P and NP are not equal.
-/
@[category research open, AMS 68]
theorem P_ne_NP : P ≠ NP := by sorry

/--
**NP ≠ coNP**:

The conjecture that the complexity classes NP and coNP are not equal.
-/
@[category research open, AMS 68]
theorem NP_ne_coNP : NP ≠ coNP := by sorry

/--
The theorem that the set of complements of languages in P is itself P.

This can be proven by observing that the boolean negation function is computable in polynomial time,
and that compositions of poly-time computable functions are also poly-time computable.
-/
@[category textbook, AMS 68]
theorem coP_eq_P :
    { L | Lᶜ ∈ P } = P := by
  sorry

/--
The theorem that P is a subset of NP.

This can be proven by observing that for any language in P,
we can construct a verifier that ignores the witness and simply runs the poly-time decider for the
language.
-/
@[category textbook, AMS 68]
theorem P_subset_NP :
    P ⊆ NP := by
  sorry

/--
The theorem that P is a subset of coNP.
-/
@[category textbook, AMS 68]
theorem P_subset_coNP :
    P ⊆ coNP := by
  rw [coNP, ← coP_eq_P]
  simp only [Set.ofPred_subset_ofPred]
  intros L hL
  exact P_subset_NP hL

end ComplexityTheory

On-site verification needs an executable Lean target. None is attached yet.

A source attachment or link is not a verified proof. The statement’s correspondence with the original question needs human review.

Proofs & verification

No Lean has been submitted for this problem yet. A Lean file can be attached to a submission for review, though with no target here it cannot be machine-checked.

Background

Source snapshot inspected on 10 September 2026. Subsequent research status and the accuracy of source formalizations have not been independently certified.

Fixed commit b82b08faa9006484021c12005ab41287fb2ffb69. This file contains 2 source-labeled research-open declarations. Other declarations in the attached file can be definitions, solved results or tests. The file is preserved as source material; it has not been compiled or proved by this import.

Copyright The Formal Conjectures Authors. Code: Apache-2.0; other original material: CC BY 4.0. Third-party sources retain their own licenses. Original source files and notices preserved.

References
  1. [1]Formal Conjectures — Conjectures in Complexity Theory link
  2. [2]Original reference cited in the formalization link
  3. [3]Original reference cited in the formalization link

Recorded progress

Add yours →

Nothing recorded yet. A pointer to a paper the entry is missing counts.

Machine attempts

0 recorded

Attempts run against the statement below and are recorded in full, including the failures. The point is to stop the next model — and the next person — from re-walking a road that is already known to end. Each attempt costs 25 credits.

No machine attempts recorded.

Sign in to run an attempt. New accounts start with enough credits for ten.

Discussion

0 notes

Notes are for clarifying the statement, flagging a missing reference, or recording why an approach fails. Claimed solutions belong in a submission, where they can be reviewed.

No notes yet.

Sign in to add a note.